A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)

Question

Responses

10−30h=0
10 minus 30 h equals 0

1,280+30h=0
1,280 plus 30 h equals 0

30h=10
30 h equals 10

1,280−30h=0

Answer 1

To find how long the water in the cooler will last, we start with the total amount of water in ounces (1,280 ounces) and subtract the total amount of water used over time (which is 30 ounces per hour multiplied by the number of hours \( h \)).

The equation representing this situation is:

\[ 1,280 - 30h = 0 \]

This equation shows that when all the water is consumed, the remaining amount will be zero.

Therefore, the correct response is:

1,280−30h=0 (1,280 minus 30 h equals 0)