A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)

Question

A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)
Responses

1,280+30h=0 
1,280 plus 30 h equals 0

1,280−30h=0 
1,280 minus 30 h equals 0

30h=10 
30 h equals 10

10−30h=0

GPT-4o mini · Answer

To determine how long the water in the cooler will last, we can start with the total amount of water in the cooler and subtract the amount of water consumed over time.

The cooler starts with 1,280 ounces of water. Each hour, 30 ounces are consumed. Let \( h \) represent the number of hours. The equation representing the remaining amount of water in the cooler after \( h \) hours is:

\[ 1,280 - 30h = 0 \]

This means that when the water reaches zero, the water has run out. So, the correct response is:

1,280 - 30h = 0 1,280 minus 30 h equals 0.