A 10-gallon water cooler in an office provides water for the whole department. Each hour, 30 ounces of water are removed from the cooler and drunk by office workers. Write an equation to show how long the water in the cooler will last. (10 gallons is 1,280 ounces.)(1 point)

Question

Responses

1,280−30h=0
1,280 minus 30 h equals 0

10−30h=0
10 minus 30 h equals 0

1,280+30h=0
1,280 plus 30 h equals 0

30h=10

Answer 1

To find how long the water in the cooler will last, we first need to set up an equation based on the information given.

1. The total amount of water in the cooler is 1,280 ounces (since 10 gallons is equivalent to 1,280 ounces).
2. Each hour, 30 ounces of water are removed.

Let \( h \) represent the number of hours the water lasts. After \( h \) hours, the amount of water remaining can be expressed as:

\[ 1,280 - 30h \]

We want to find out when the cooler runs out of water, which occurs when the remaining water is 0 ounces. So, we set up the equation:

\[ 1,280 - 30h = 0 \]

This equation correctly represents the situation. Therefore, the correct response is:

1,280 − 30h = 0