A 1.60-kg bottle of vintage wine is lying horizontally in a rack. The two surfaces on which the bottle rests are 90.0° apart, and the right surface makes an angle of 45.0° with respect to the horizontal. Each surface exerts a force on the bottle that is perpendicular to the surface. Both forces have the same magnitude F. Find the value of F. Assume g = 9.81 m/s2.

asked by Tiffany

14 years ago

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1 answer

F1=F2

F1= Fn*sin45
= (1.60kg x 9.81 m/s^2) * sin45
= 11.10 N

answered by aprilann

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Question

A 1.60-kg bottle of vintage wine is lying horizontally in a rack. The two surfaces on which the bottle rests are 90.0° apart, and the right surface makes an angle of 45.0° with respect to the horizontal. Each surface exerts a force on the bottle that is perpendicular to the surface. Both forces have the same magnitude F. Find the value of F. Assume g = 9.81 m/s2.

1 answer

F1=F2

F1= Fn*sin45
= (1.60kg x 9.81 m/s^2) * sin45
= 11.10 N

Ask a New Question or answer this question.

aprilann · Answer

F1=F2 F1= Fn*sin45 = (1.60kg x 9.81 m/s^2) * sin45 = 11.10 N