A 1.0-kg cart and a 0.50-kg cart sit at different positions on a low-friction track. You push on the 1.0-kg cart with a constant 2.5-N force for 0.15m . You then remove your hand, and the cart slides 0.35 m and strikes the 0.50-kg cart.
By what amount does your force change the kinetic energy of the system's center of mass?
This is the third part of a question, If it helps part 1 found a work of 0.375 J and part two found a change in center of mass by .1 meters. I thought that the change in K would be 0.375 J because work equals change in K but it doesnt seem to be correct, I also solved for it and got that it should be 0.375 J.
3 answers
67
.3N
Did you find an answer for kinetic energy?
0 answers