A 0.65m long cord exerts a centripetal force of 11.6 N on a 0.10 kg mass tied to the end of the cord. What is the tangential and angular velocity of the mass?

Answer 1

11.6 = m v^2/R = 0.1 * v^2 / 0.65
so
v^2 = 75.4
v = 8.68 m/s
omega =v/R