OCl-1 + I-1 + ……. -> Cl-1 + ……. + ……..
OCl^- + 2e- + 2H^+ ==> Cl^- + H2O (one half equation)
2I^- ==> I2 + 2e (2nd half equation).
Add the two half equations, cancel the two electrons, and you have the final equation.
A 0.6465 g of bleaching powder Ca(ClO)2 was dissolved in dilute acid and treated with excess potassium iodide the reaction is:
OCl-1 + I-1 + ……. -> Cl-1 + ……. + ……..
1) complete and balance the above reaction .
thank you!
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