Asked by Alice
Iron metal is dissolved in dilute aqueous HCl. The resulting solution is warmed with dilute nitric acid and then treated with aqueous potassium iodide. Write equations for the reactions.
Ok so for the first step I got:
Fe + 2HCl --> FeCl2 + H2
I'm guessing that when nitric acid is added the Fe2+ will be oxidised to Fe3+, but I don't know whether it will be in a compound with the Cl- or the NO3-. When potassium iodide is added I think that the Fe3+ will be reduced and the iodide will be oxidised to iodine but again I'm not sure how to put all this together.
Ok so for the first step I got:
Fe + 2HCl --> FeCl2 + H2
I'm guessing that when nitric acid is added the Fe2+ will be oxidised to Fe3+, but I don't know whether it will be in a compound with the Cl- or the NO3-. When potassium iodide is added I think that the Fe3+ will be reduced and the iodide will be oxidised to iodine but again I'm not sure how to put all this together.
Answers
Answered by
DrBob222
Sounds good to me. If you write inic equations you don't need to worry about where to place the nitrate and chloride ions.
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