When iron metal reacts with oxygen, the reaction can form Fe203. The balanced chemical equation I think is right is 4 Fe + 302----2Fe203. So I have 4 moles of iron + 3 moles of oxygen creates 2 moles of iron oxide. I need to find the number of moles of oxygen that are needed to form 6 mol of Fe203. Could you show all work so I can understand?

asked by Steve

8 years ago

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1 answer

do it as a proportion:
6molFe2O3/2molFe2O3 as ?/3molO2
?=9molesO2

answered by bobpursley

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Question

When iron metal reacts with oxygen, the reaction can form Fe203. The balanced chemical equation I think is right is 4 Fe + 302----2Fe203. So I have 4 moles of iron + 3 moles of oxygen creates 2 moles of iron oxide. I need to find the number of moles of oxygen that are needed to form 6 mol of Fe203. Could you show all work so I can understand?

1 answer

do it as a proportion:
6molFe2O3/2molFe2O3 as ?/3molO2
?=9molesO2

bobpursley · Answer

do it as a proportion: 6molFe2O3/2molFe2O3 as ?/3molO2 ?=9molesO2