A 0.60-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 9.0 N for a distance of 2.0 m. How much farther would the force have to act for the block to have 72 J of kinetic energy?

5 answers

work = energy

72 J / 9 N = 8 m
It's not correct, that´s what the platform says
Did not subtract work already done
9*2 = 18 J
72 - 18 = 54
54/9 = 6 meters
@Damon thanks a lot!
You are welcome.