If a 0.50-kg block initially at rest on a frictionless, horizontal surface is acted upon by a force of 8.0 N for a distance of 4 m, then what would be the block's velocity?

Answer 1

a = F/M = 8/0.5 = 16 m/s^2

V^2 = Vo + 2a*d
Vo = 0
a = 16 m/s^2
d = 4 m.
Solve for V(m/s).