A 0.410-kg soccer ball is kicked at an initial speed of 32.5 m/s at an angle of 33.0° to the horizontal. What is the kinetic energy of the soccer ball when it has reached the apex of its trajectory?

Answer 1

Vo = 32.5m/s[33o].
Xo = 32.5*Cos33 = 27.5m/s = Hor. component of initial velocity.

Y = 0 = Ver. component of velocity at max. ht.(apex).

V = Xo + Yi = Xo + 0 = Xo = 27.3 m/s = Velocity at max. ht.

KE = 0.5M*V^2 = 0.5*0.41*27.3^2 =