Asked by Sarah

A 0.25 mol/L solution of benzoic acid, KC7H5O2 and antiseptic also used as a food preservative, has a pH of 2.40. Calculate the Ka of benzoic acid at SATP

How does the benzoic acid ionization go?
Answered by DrBob222
C6H5COOH ==> C6H5COO^- + H^+
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