Q = .25 * specific heat of iron * (45-23)
You have those specific heats in Joules and Calories in your text
A 0.25 kg cube of iron is heated and its temperature rises from 23.0 C to 45.0 C. How much heat entered the cube in Joules and in Calories?
5 answers
just multiply then??
Yes
iron
470 J/kg K
470 J/kg K
iron
470 J/kg K
108 cal/kg K
470 J/kg K
108 cal/kg K