energy in = 2263 J = rise in temp * 0.449 J/g deg C * 252 g
so
rise in temp = 2263 / (.449 * 252) = 20 degrees C
547 + 20 = 567 degrees C
A ball of iron with a mass of 252 g was heated using 2263 J of energy. The initial temperature was 547 deg * C What was the final temperature of the Iron? (The specific heat capacity for iron is 0.449 * J/(g deg * C) ,) (1 point)
24.8 ^ (- C)
O - 527 ^ (- C)
O 567 deg * C
0.04 deg * C
1 answer
1 answer