HA ==> H^+ + A^-
Ka = (H^+)(A^-)/(HA)
Convert pH to H^+, substitute that for H^+ and A^- in the equation for Ka. For HA, substitute 0.23-H^+ and solve for Ka.
A 0.23 M solution of a weak acid has a pH of 2.89. What is the Ka(acid ionization constant)for this acid?
2 answers
How do I convert pH to H^+?