A 0.23 kg ball of dough is thrown straight up into the air with an initial velocity of 12 m/s.Find the momentum of the ball of dough halfway to its maximum height on the way up.

Answer 1

KE at half height=
1/2 m v^2=1/2 (1/2 m 12^2)
or v= sqrt(1/2 144)=sqrt72

momentum at half height:
.23*sqrt72

check that.

Answer 2

what is sqrt??

Answer 3

Square Root