HA + NaOH ==> NaA + H2O
moles NaOH added = M x L = ??
moles HA must be the same (see the coefficients in the balanced equation).
moles HA = grams/molar mass
You know moles HA and grams HA, solve for molar mass.
A 0.225g sample of a weak monoprotic acid requires 37.50 mL of 0.100 M NaOH solution to reach the equivalence point. What is the molar mass of the acid?
1 answer
1 answer