The correct answer is D. 7.8N.
We can use the formula F = m*a, where F is the force, m is the mass, and a is the acceleration.
Plugging in the given values, we get:
F = 0.2 kg * 8 m/s^2 = 1.6 N/s^2 = 7.8 N
Therefore, the force with which the ball will hit the catcher's mitt is 7.8 N.
A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point
A. 8.2 N
B. 1.6 N
C. 40 N
D. 7.8N
1 answer
1 answer