A 0.2-kilogram softball is thrown toward a catcher’s mitt. The ball is accelerating at a rate of 8 meters per second squared. With what force will the ball hit the catcher’s mitt?(1 point)

Question

Responses

8.2 N
8.2 N

1.6 N
1.6 N

7.8 N
7.8 N

40 N

Answer 1

To find the force acting on the softball, we can use Newton's second law of motion, which states that \( F = m \times a \), where:

• \( F \) is the force,
• \( m \) is the mass of the object, and
• \( a \) is the acceleration.

Given:

• \( m = 0.2 \) kg (mass of the softball)
• \( a = 8 \) m/s² (acceleration)

Now, we can calculate the force:

\[ F = 0.2 , \text{kg} \times 8 , \text{m/s}^2 = 1.6 , \text{N} \]

Therefore, the force with which the ball will hit the catcher’s mitt is 1.6 N.