A 0.157kg ball is thrown straight up from 1.81m above the ground. Its initial vertical speed is 10.40m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.

Answer 1

(ball weight, N)x (elevation change)

= 0.157*9.8*1.81 = 2.785 Joules

The initial speed does not matter.