h=v²/2g=5.6²/2•9.8 =1.6m.
Upward motion
W1=-mgh= - 0.135•9.8•1.6= - 2.12 J
Downward motion
W2= mg(H+h) = 0.135•9.8•(1.94+1.6) =4.68 J
W= W1+W2 = -2.12 +4.68 = 2.56 J.
A 0.135 kg ball is thrown straight up from 1.94m above the ground. Its initial vertical speed is 5.60 m/s. A short time later, it hits the ground. Calculate the total work done by the force of gravity during that time.
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