The gravitational force can be calculated using the following formula:
F = m * g
where F is the gravitational force, m is the mass of the baseball (0.150 kg), and g is the acceleration due to gravity (approximately 9.81 m/s²).
First, we need to find the maximum height the ball reaches. We can use the following kinematic equation:
v^2 = u^2 + 2*a*s
where v is the final velocity (0 m/s at the peak), u is the initial velocity (20 m/s), a is the acceleration due to gravity (which is -9.81 m/s², since it's acting downward), and s is the maximum height.
Solving for s, we get:
0 = 20^2 - 2*9.81*s
s = (20^2)/(2*9.81)
s ≈ 20.3 m
The height where we need to calculate the force is half the maximum height, which is:
s_half = 20.3 / 2
s_half ≈ 10.15 m
However, the gravitational force is the same at all heights, so we can calculate it as follows:
F = 0.150 kg * 9.81 m/s²
F ≈ 1.47 N
The force on the ball when it reaches half its maximum height is approximately 1.47 N, acting downward. Since there are no other forces acting on the ball, aside from gravity, the force on the ball when it reaches its peak is also approximately 1.47 N, acting downward.
A 0.150kg baseball is thrown upwards with an initial speed of 20.0 m/s. What is the force on the ball when it reaches half its maximum height? (Disregard air resistance.) What is the force on the ball when it reaches its peak?
The force on the ball is gravitational weight, that what makes is slow down going up, and speed up when it falls.
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