A 0.145-kg baseball traveling 35.0 m/s strikes the catcher's mitt which, in bring the ball to rest, recoils backward 11.0 cm. What was the average force applied by the ball on the glove?

Answer 1

The kinetic energy of the baseball is converted to work pushing the catcher's glove. That work equals Fav*X
where Fav is the average force and X is the distance moved by the glove.

Thus

Fav = (M/2) V^2/X

Answer 2

807.4 N ?

Answer 3

Where could i find the answer?