A 0.130 kg baseball, traveling 35.0 m/s, strikes the catcher's mitt, which recoils 11.0 cm in bringing the ball to rest. What was the average force (in newtons) applied by the ball to the mitt?

Answer 1

Work done against mitt equals initial kinetic energy

F*X = (1/2) M V^2

X is the recoil distance in meters.

Solve for the force F, in Newtons

Answer 2

7.24

Answer 3

I got the same answer, but are sure this is the equation? I tried to use it with a similar problem, .140 kg baseball, traveling 35 m/s which recoils the mitt 17 cm and I keep getting the wrong answer

Answer 4

Okay sorry I figured it out, I was dividing by the X value in cm not m, in which case would cause the answer for the above to be 723.86 N not 7.24.