A 0.11kg mass is vibrating at the end of a horizontal spring along a frictionless surface. If the spring constant is 0.52 N/m, what is the displacement of the mass when the acceleration of the mass is 0.25m/s^2?

Answer 1

Acceleration - -w^2 * (displacement)

The angular frequency of vibration, in radians/s, is sqrt(k/m) = 2.17 rad/s

Solve for the displacement, X

X = -(acceleration) * (m/k)

Answer 2

205