A 0.026 kg golf ball moving at 19.6 m/s crashes through the window of a house in 5.6 10-4 s. After the crash, the ball continues in the same direction with a speed of 8.2 m/s. Assuming the force exerted on the ball by the window was constant, what was the magnitude of this force?p

Answer 1

a = (V-Vo)/t
a=(8.2-19.6)/5.6*10^-4 =-2.04*10^4m/s^2

Fe = m*a=0.025 * (-2.04*10^4=-510 N.= Force exerted.

Answer 2

Correction: Change 0.025 to 0.026 and get 530.4 N.