A 0.025 kg golf ball moving at 27 m/s crashes through the window of a house in 5.0 10-4 s. After the crash, the ball continues in the same direction with a speed of 10 m/s. Assuming the force exerted on the ball by the window was constant, what was the magnitude of this force?

Question

A 0.025 kg golf ball moving at 27 m/s crashes through the window of a house in 5.0  10-4 s. After the crash, the ball continues in the same direction with a speed of 10 m/s. Assuming the force exerted on the ball by the window was constant, what was the magnitude of this force?

cyrus · Accepted Answer

1850 N

Haley · Answer

m= .025 kg initial velocity= 27 m/s time= 5.0*10^-4 final velocity= 10 m/s Force*time=mass( final vecolicy - negative initial velocity) F(5.0*10^-4)=(.025)(10-(-27)) F=(.025)(10-(-27))/(5.0*10^-4)