Question
A pilot is flying at 10,000 feet and wants to take the plane up to 20,000 feet over the next 50 miles. What should be his angle of elevation to the nearest tenth?
Answers
Henry
d = 50mi * 5280Ft/m1 = 264,000 Ft. =
264K.
(0,10k), (264k,20k).
Tan A = (20k-10k)/(264k-0) = 0.037879
A = 2.2 Degrees.
264K.
(0,10k), (264k,20k).
Tan A = (20k-10k)/(264k-0) = 0.037879
A = 2.2 Degrees.