Asked by Monk
A pilot is flying at 200 miles per hour (airspeed), and wants his flight path (course or actual direction) to be on a bearing of 237 degrees. A wind is blowing for the north at 40 miles per hour. Find the bearing he should fly, and find the plane's ground speed. Include a labeled drawing.
Answers
Answered by
Henry
Vp + 40mi/h[180] = 200mi/h[237o].
Vp + 40*sin180 + i40*Cos180 = 200*sin237 + i200*Cos237,
Vp + 0 -40i = -167.7 - 108.9i,
Vp = -167.7 - 68.9i =181.3mi/h[67.7o] S. of W. = 181.3mi/h[202.3o] CW.
Vp + 40*sin180 + i40*Cos180 = 200*sin237 + i200*Cos237,
Vp + 0 -40i = -167.7 - 108.9i,
Vp = -167.7 - 68.9i =181.3mi/h[67.7o] S. of W. = 181.3mi/h[202.3o] CW.
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