Question
In a vacuum, two particles have charges of q1 and q2, where q1 = +3.7 µC. They are separated by a distance of 0.22 m, and particle 1 experiences an attractive force of 3.5 N. What is q2 (magnitude and sign)?
Answers
force=kq1q2/distance^2 solve for q2. if the force on q1 is attractive, q2 has to be negative.
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