Question

A closed container with a volume of 8000cm^3 is filled with Xenon gas. the temperature is 273K and the pressure is 2 atm. How many moles of Xenon are in the container?

The container is now submerged in boiling water until the gas inside the container is at 373K. What is the pressure of the Xenon?

Thanks for your help.
V=8000cm³=8•10⁻³m³
p=2 atm= 2.03•10⁵Pa
T=273 K

ν=pV/RT = 2.03•10⁵•8•10⁻³/273•8.31 =
= 0.716 moles

V=const
p₁/T₁=p/T
p₁=T₁p/T=373•2.03•10⁵/273 =2.77•10⁵Pa

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