CO2(g) + H2(g) equilibrium reaction arrow CO(g) + H2O(g)

Question

Calculate the equilibrium concentration of each compound if 2.00 moles of CO2 and 2.40 moles of H2 are placed in a 3.90 liter container at 300°C. Kc = 2.30 for the reaction at this temperature.
[CO2] = M
[H2] = M
[CO] = M
[H2O] = M

Answer 1

2.00/3.90 = about 0.512M = (CO2)
2.40/3.90 = about 0.615M = (H2)

.......CO2(g) + H2(g) ==> CO(g) + H2O(g)
I.....0.512....0.615.......0........0
C.......-x.......-x........x........x
E....0.512-x..0.615-x......x........x

Substitute the E line into the Kc expression and solve for x and go from there.