Asked by Morgan
1.8 mol Zn and 7.3 mol HCl react according
to the equation
Zn + 2 HCl −→ ZnCl2 + H2 .
If the limiting reactant is Zn, calculate the
amount of ZnCl2 formed.
Answer in units of mol
to the equation
Zn + 2 HCl −→ ZnCl2 + H2 .
If the limiting reactant is Zn, calculate the
amount of ZnCl2 formed.
Answer in units of mol
Answers
Answered by
Anonymous
answer is 8
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