Question

Solve
log base 2 of (3x-1) - log base 2 of x = -2

Answer 1

then

log₂ ((3x-1)/x) = -2
2^-2 = (3x-1)/x
1/4 = (3x-1)/x
12x - 4 = x
11x = 4

x = 4/11