Asked by Lilly

Solve
log base 2 of (3x-1) - log base 2 of x = -2

Answers

Answered by Reiny
then

log<sub>2</sub> ((3x-1)/x) = -2
2^-2 = (3x-1)/x
1/4 = (3x-1)/x
12x - 4 = x
11x = 4

x = 4/11
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