solve it:

Question

a) 3 log x with base 8 + 2 = 0
b)2 log (x-1)with base 6 =log 4 with base 6

Answer 1

a)
3 log₈ x = -2
log₈ x = -2/3
8^(-2/3) = x
x = 1/4

b) 2 log₆ (x-1) = log₆ 4
log₆ (x-1)^2 = log₆ 4

(x-1)^2 = 4
x-1 = ±2
x = 3 or x = -1 , but for log(x-1) to be defined, x>1

so x = 3