Asked by Kong
solve it:
a) 3 log x with base 8 + 2 = 0
b)2 log (x-1)with base 6 =log 4 with base 6
a) 3 log x with base 8 + 2 = 0
b)2 log (x-1)with base 6 =log 4 with base 6
Answers
Answered by
Reiny
a)
3 log<sub>8</sub> x = -2
log<sub>8</sub> x = -2/3
8^(-2/3) = x
x = 1/4
b) 2 log<sub>6</sub> (x-1) = log<sub>6</sub> 4
log<sub>6</sub> (x-1)^2 = log<sub>6</sub> 4
(x-1)^2 = 4
x-1 = ±2
x = 3 or x = -1 , but for log(x-1) to be defined, x>1
so x = 3
3 log<sub>8</sub> x = -2
log<sub>8</sub> x = -2/3
8^(-2/3) = x
x = 1/4
b) 2 log<sub>6</sub> (x-1) = log<sub>6</sub> 4
log<sub>6</sub> (x-1)^2 = log<sub>6</sub> 4
(x-1)^2 = 4
x-1 = ±2
x = 3 or x = -1 , but for log(x-1) to be defined, x>1
so x = 3
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