Asked by confuse
I don't know what terms are suppose to be conbine with each other or find the lcd in this problem.
(3b-2)/(b+1)=4-(b+2)/(b-1)
(3b-2)/(b+1)=4-(b+2)/(b-1)
Answers
Answered by
Reiny
the lcd is (b+1)(b-1), so multiply each term by it to get
(3b-2)(b-1) = 4(b^2-1) - (b+2)(b+1)
expand and simplify to solve,
I got b=4
(3b-2)(b-1) = 4(b^2-1) - (b+2)(b+1)
expand and simplify to solve,
I got b=4
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