Asked by Bash

The first three terms of a GP are also the first,nineth and eleventh terms respectively of an AP. Given that the terms of the GP are all different,find the common ratio r,if the sum to infinity of the GP is 8. Find also the first term and the common difference of the AP.

Answers

Answered by Steve
Both sequences start with a

ar = a+8d
ar^2 = a+10d
a/1-r = 8

a = 6
r = 1/4
d = -9/16

a/1-r = 6/(3/4) = 8
GP: 6 3/2 3/8 ...
AP: 6 87/16 78/16 69/16 60/16 51/16 42/16 33/16 24/16 15/16 6/16 ...

Note that 24/16 = 3/2 and 6/16 = 3/8
Answered by Lia
I don't get his solution
Answered by Good
I don’t get his solution
Answered by MonXD
I don’t get this solution ;—;
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