Asked by Lindsay

Solve 16(4^2x-1)= 8^x+3
Answered by Damon
I do not trust your parentheses
eg:
8^(x) + 3 or 8^(x+3)
or
4^(2x) -1 or 4^(2x-1)
Answered by Damon
if it is

16 [ 4^(2x-1) ] = 8^(x+3)

that is

2^4 [ 2^(4x-2) ] = 2^[3(x+3)]

2^[16x-8] = 2^[3x+9]

or
16-x = 3x+9
Answered by Damon
16x-8 = 3x+9
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