Question
1. Brothers Bob and Tom buy a tent that has a center pole of 6.25 feet high. If the sides of the tent are supposed to make a 50deg angle with the ground, how wide is the tent?
2. A swimming pool is 30 meters long and 12 meters wide. The bottom of the pool is slanted so that the water depth is 1.3 meters at the shallow end and 3 meters at the deep end. Find the angle of depression at the bottom of the pool.
2. A swimming pool is 30 meters long and 12 meters wide. The bottom of the pool is slanted so that the water depth is 1.3 meters at the shallow end and 3 meters at the deep end. Find the angle of depression at the bottom of the pool.
Answers
1. let the width of the tent be 2x
from my diagram,
tan 50° = 6.25/x
x = 6.25/tan50 = 5.24
So the tent is 2(5.24) appr 10.5 ft wide
2 make a diagram showing a side-view of the pool
Draw a line parallel to the surface of the pool from the shallow end to the deep end, giving you a right-angled triangle
let the angle be Ø
tanØ = 1.7/30 = .05666..
Ø = 3.24°
(notice the width of the pool does not enter the picture)
from my diagram,
tan 50° = 6.25/x
x = 6.25/tan50 = 5.24
So the tent is 2(5.24) appr 10.5 ft wide
2 make a diagram showing a side-view of the pool
Draw a line parallel to the surface of the pool from the shallow end to the deep end, giving you a right-angled triangle
let the angle be Ø
tanØ = 1.7/30 = .05666..
Ø = 3.24°
(notice the width of the pool does not enter the picture)
Nobody is going to see this but WHY ISN'T THAT WIDTH IN THE PICTURE IS IT THE HYPOTENUSE SO MANY QUESTIONS?!?!?!