Asked by Ethan
A cylindrical slime tank is placed so that the axis of the cylinder is horizontal. Find the fluid force on a circular end of the tank if the tank is half full, assuming that the diameter is 6 feet and the slime weighs 54 pounds per cubic feet?
Answers
Answered by
Steve
an excellent presentation on this topic, with a video, even, is at
http://www.sophia.org/tutorials/fluid-force-integral-calculation
Plug in your numbers, and c'mon back if you get stuck. And show how far you got.
http://www.sophia.org/tutorials/fluid-force-integral-calculation
Plug in your numbers, and c'mon back if you get stuck. And show how far you got.
Answered by
Ethan
I did the problem.
I found the fluid force to be 54 times the integral from -3 to 0 of (-y)(2)(root(9-y^2)dy
my final answer was 972 pounds. Is that correct?
note from my work:
h(y)=-y
L(y)=2x=2root(9-y^2)
I found the fluid force to be 54 times the integral from -3 to 0 of (-y)(2)(root(9-y^2)dy
my final answer was 972 pounds. Is that correct?
note from my work:
h(y)=-y
L(y)=2x=2root(9-y^2)
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