Asked by Dee
Solve the system, if possible. (If the system is inconsistent, enter INCONSISTENT. If the system is dependent, enter a general solution in terms of x, y, or z.)
x + y + z = 7
2x + y + z = 14
x + 2y + 3z = 2
x + y + z = 7
2x + y + z = 14
x + 2y + 3z = 2
Answers
Answered by
Damon
none of those lines is parallel, so I should be able to find a solution.
first work on the first two by elimination
x + y + z = 7
2x + y + z = 14
---------------- subtract
- x + 0 + 0 = -7
so
x = 7
well that gives us a running start
7 + y + z = 7
14 + y + z = 14
both yield
y + z = 0 so z = -y
now the last equation with x = 7 and z = -y
7 + 2 y + 3(-y) = 2
-y = -5
so
y = 5
and
z = -y = -5
first work on the first two by elimination
x + y + z = 7
2x + y + z = 14
---------------- subtract
- x + 0 + 0 = -7
so
x = 7
well that gives us a running start
7 + y + z = 7
14 + y + z = 14
both yield
y + z = 0 so z = -y
now the last equation with x = 7 and z = -y
7 + 2 y + 3(-y) = 2
-y = -5
so
y = 5
and
z = -y = -5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.