Asked by Jessy
Complete the square to find the vertex of each quadratic function. State the vertex.
y=-x^2+5x-3
y= 5x^2+1/5x-10
2x^2+8x-2
y=-x^2+5x-3
y= 5x^2+1/5x-10
2x^2+8x-2
Answers
Answered by
Steve
-x^2+5x-3
-(x^2-5x)-3
-(x^2-5x+(5/2)^2)-3+(5/2)^2
-(x-5/2)^2 - 3+25/4
-(x-5/2)^2 +13/4
5x^2+1/5 x - 10
5(x^2 + 1/25 x + 1/50^2) - 10 - 5(1/50^2)
5(x + 1/50)^2 - 10 - 1/500
5(x+1/50)^2 - 5001/500
2x^2+8x-2
2(x^2+4x)-2
2(x^2+4x+4) - 2 - 2(4)
2(x+2)^2 - 10
-(x^2-5x)-3
-(x^2-5x+(5/2)^2)-3+(5/2)^2
-(x-5/2)^2 - 3+25/4
-(x-5/2)^2 +13/4
5x^2+1/5 x - 10
5(x^2 + 1/25 x + 1/50^2) - 10 - 5(1/50^2)
5(x + 1/50)^2 - 10 - 1/500
5(x+1/50)^2 - 5001/500
2x^2+8x-2
2(x^2+4x)-2
2(x^2+4x+4) - 2 - 2(4)
2(x+2)^2 - 10
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