Help with vectors, please. Thanks

1) Express point in rectangular form. Give EXACT answer, if possible?
(2, 4π /11)

2) Given P = (2. -3) and Q = (-3, -4). find the component form of vector PQ

3) The vector v has a magnitude of 25 inches and a direction of 32° , Express this vector in rectangular form.

perform each operation with vectors u = < 6, 2 > and v = < -10, 1 >
4) u+v 5) -3u

User Icon for Steve Steve answered
10 years ago

(x,y) = (2cos 4π/11,2sin 4π/11)

P = (√26,arctan(-1/-5))

v = 25cos32°i + 25cos32°j

u+v = <(6-10),(2+1)>
-3u = <-3(6),-3(2)>

User Icon for Lilly Lilly answered
10 years ago

Thanks.

For #3, I did not realize he gave me multiple choice answers.
A) (-13.25, 21.20)
B) (-21.20, -13.25)
C) (13.25, 21.20)
D) (21.20, 13.25)

User Icon for Lilly Lilly answered
10 years ago

I figured it out and think both have to be positive so the answer is D. Let me know if I'm wrong

User Icon for Steve Steve answered
10 years ago

Looks good to me.

User Icon for Explain Bot Explain Bot answered
11 months ago

Sure, I can help you with vectors. Let's go through each question one by one:

1) To express a point in rectangular form, you need to convert it from polar form. In this case, the point is given as (2, 4π/11).

To convert it to rectangular form, you can use the following formulas:
x = r * cos(θ)
y = r * sin(θ)

In this case, r = 2 and θ = 4π/11. Plugging these values into the formulas gives us:
x = 2 * cos(4π/11)
y = 2 * sin(4π/11)

To get the exact answer, you can leave it in this form. If you want a numerical approximation, you can use a calculator to evaluate the trigonometric functions.

2) To find the component form of vector PQ, you need to subtract the coordinates of point P from the coordinates of point Q. Given P = (2, -3) and Q = (-3, -4), the component form of vector PQ is:

PQ = (-3 - 2, -4 - (-3))
= (-5, -1)

So the component form of PQ is (-5, -1).

3) To express a vector with magnitude 25 inches and direction 32° in rectangular form, you can use the following formulas:

x = magnitude * cos(direction)
y = magnitude * sin(direction)

In this case, the magnitude is 25 inches and the direction is 32°. Plugging these values into the formulas gives us:
x = 25 * cos(32°)
y = 25 * sin(32°)

Performing the calculations will give you the rectangular form of the vector.

4) To perform vector addition (u + v), you simply add the corresponding components of the vectors. Given u = <6, 2> and v = <-10, 1>, the sum of u and v is:

u + v = <6 + (-10), 2 + 1>
= <-4, 3>

So u + v is equal to <-4, 3>.

5) To multiply a vector by a scalar (-3u), you simply multiply each component of the vector by the scalar. Given u = <6, 2>, multiplying u by -3 gives:

-3u = <-3 * 6, -3 * 2>
= <-18, -6>

So -3u is equal to <-18, -6>.

I hope this helps! Let me know if you have any further questions.