Asked by Anonymous
Find the equation to the curve that joins the following points.
(1,1),(0,1),(2,5),(-1,-5)
(1,1),(0,1),(2,5),(-1,-5)
Answers
Answered by
Steve
assuming you want a polynomial of lowest degree, that would be a cubic
y=ax^3+bx^2+cx+d
(1,1): a+b+c+d=1
(0,1): d=1
(2,5): 8a+4b+2c+d=5
(-1,-5): -a+b-c+d=-5
solve the system to get (and avoiding fractions)
3y = 5x^3-9x^2+4x+3
y=ax^3+bx^2+cx+d
(1,1): a+b+c+d=1
(0,1): d=1
(2,5): 8a+4b+2c+d=5
(-1,-5): -a+b-c+d=-5
solve the system to get (and avoiding fractions)
3y = 5x^3-9x^2+4x+3
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