Asked by Abby
Find an equation of the curve whose tangent line has a slope of f'(x) =2x^-10/11, given that the point (-1,-4) is on the curve.
Answers
Answered by
oobleck
Your function is not written correctly, since (-1,-4) does not satisfy the equation. Try again.
In any case, f(x) is the antiderivative, and you can use the point to determine C.
In any case, f(x) is the antiderivative, and you can use the point to determine C.
Answered by
Damon
maybe f'(x) = (2 x^-10)/11 ?
y = [(2/-9) x^-9 ]/11 + c
-4/2 = [1/ (-1)^9 ] /99 - c/2
-2 = -1/99 - c/2
c/2 = 1/99
c = 2/99
y = [(2/-9) x^-9 ]/11 + 2/99
y = -2 /99 x^-9 + 2/99
99 y = -2x^-9 + 2
y = [(2/-9) x^-9 ]/11 + c
-4/2 = [1/ (-1)^9 ] /99 - c/2
-2 = -1/99 - c/2
c/2 = 1/99
c = 2/99
y = [(2/-9) x^-9 ]/11 + 2/99
y = -2 /99 x^-9 + 2/99
99 y = -2x^-9 + 2
Answered by
oobleck
duh. what was I thinking? SMH
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