Asked by Anonymous
Suppose a driver's car needs to travel 46.4 miles in 1.000 hour at a constant speed. If the tires of the car have a rolling radius of 28.4 cm, what will be the period of rotation of each tire?
Suppose a moon of a planet in a distant solar system has an average orbital radius of 2.62 x 108 m. If it completes its orbit in 20.1 earth days, what is the average gravitational acceleration keeping it in orbit around the planet?
Suppose a moon of a planet in a distant solar system has an average orbital radius of 2.62 x 108 m. If it completes its orbit in 20.1 earth days, what is the average gravitational acceleration keeping it in orbit around the planet?
Answers
Answered by
Henry
Vc = 46.4mi/3600s * 1600m/mi = 20.62 m/s
Circumference=pi*2r=3.14 * 0.568=1.784 m
Period =(1.784m/20.62m)*1s. = 0.0865 s.
Circumference=pi*2r=3.14 * 0.568=1.784 m
Period =(1.784m/20.62m)*1s. = 0.0865 s.
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