Asked by Iman

The specific heat for liquid ethanol is 2.46 J/(g•°C). When 210 g of ethanol is cooled from 50 °C to 5 °C, the surrounding 7.80 × 103 g of air absorbs the heat. The specific heat of air is 1.01J/(g•°C)
Answered by DrBob222
You don't have a question. I assume you want to determine the change in T of the air.
heat lost by ethanol + heat gained by air = 0

[mass ethanol x specific heat ethanol x (Tfinal-Tinitial)] + [mass air x specific heat air x (Tfinal-Tinitial)] = 0
Substitute the values from the problem and solve for (Tfinal-Tinitial) air (or delta T = change in T).
Answered by Anonymous
0.656 C
Answered by Anonymous


The specific heat for liquid ethanol is 2.46 J/(g•°C). When 210 g of ethanol is cooled from 50 °C to 5 °C, the surrounding 7.80 × 103 g of air absorbs the heat. The specific heat of air is 1.01J/(g•°C). What is the change in air temperature, assuming all the heat released by the ethanol is absorbed by the air?
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