Question

0=-16t^2+80t+96

Solve for t.

Can someone please show me the steps on how to do this I can not seem to get it right.

Thanks!!

Answer 1

imagine at^2+bt+c

t = ( -b +- sqrt((b^2)-(4ac)) )/ 2a

you will have to possible answer

Answer 2

0= -16( t^2 -5t -6)
0 = -16(t+ 1)(t-6)

t + 1 = 0
t + 1 -1 = 0-1

t = -1 Does not make sense you can ignore when t is -1


t -6 = 0
t -6 + 6 = 6
t = 6
t = 6 seconds