Asked by Anonymous
Identify which lines are parallel.
1. y = 6; y = 6x + 5; y = 6x - 7; y = -8
A: y = 6; y = -8; y = 6x +5; y = 6x - 7 (all)
2. y = 3/4x - 1; y = -2x; y - 3 = 3/4(x - 5); y - 4 = -2(x + 2)
A: y = 3/4x - 1; y- 3 = 3/4(x -5)
Identify which lines are perpendicular.
3. y = 2/3x - 4; y = -3/2x + 2; y = -1; x = 3
A: y = 2/3x - 4; y = -3/2x + 2; y = -1; x = 3 (all)
4. y = -3/7x - 4; y - 4 = -7(x + 2); y - 1 = 1/7(x - 4); y - 7 = 7/3(x - 3)
A: y = -3/7x - 4; y - 4 = -7(x + 2); y - 1 = 1/7(x - 4); y - 7 = 7/3(x - 3) (all)
5. Show that PQRS is a rectangle.
(P: (1,4); Q: (2,6); R: (8,3); S: (7,1)
A: PQ is perpendicular to QR because 2(-1/2) = -1. RS is perpendicular to PS because 2(-1/2) = -1. Therefore. RQRS is a rectangle because it contains a right angle.
1. y = 6; y = 6x + 5; y = 6x - 7; y = -8
A: y = 6; y = -8; y = 6x +5; y = 6x - 7 (all)
2. y = 3/4x - 1; y = -2x; y - 3 = 3/4(x - 5); y - 4 = -2(x + 2)
A: y = 3/4x - 1; y- 3 = 3/4(x -5)
Identify which lines are perpendicular.
3. y = 2/3x - 4; y = -3/2x + 2; y = -1; x = 3
A: y = 2/3x - 4; y = -3/2x + 2; y = -1; x = 3 (all)
4. y = -3/7x - 4; y - 4 = -7(x + 2); y - 1 = 1/7(x - 4); y - 7 = 7/3(x - 3)
A: y = -3/7x - 4; y - 4 = -7(x + 2); y - 1 = 1/7(x - 4); y - 7 = 7/3(x - 3) (all)
5. Show that PQRS is a rectangle.
(P: (1,4); Q: (2,6); R: (8,3); S: (7,1)
A: PQ is perpendicular to QR because 2(-1/2) = -1. RS is perpendicular to PS because 2(-1/2) = -1. Therefore. RQRS is a rectangle because it contains a right angle.
Answers
Answered by
bobpursley
on 2, isn't all lines parallel?
on 4, I don't see negative reciprocals.
on 5.
slope PQ = deltay/deltax=-2/-1=2
slope QR= 3/-6=-1/2
slope RS=2/1=2
slope SP=-3/6=-1/2
SP is perpendcular to RS and PQ, and sp is parallel to qr
on 4, I don't see negative reciprocals.
on 5.
slope PQ = deltay/deltax=-2/-1=2
slope QR= 3/-6=-1/2
slope RS=2/1=2
slope SP=-3/6=-1/2
SP is perpendcular to RS and PQ, and sp is parallel to qr
Answered by
Anonymous
Reiny?
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